Sunday, December 11, 2011

Calculate percent composition of ethanol .

To determine the percent composition of ethanol, we need
to determine the weight of each element from ethanol.


We'll
write the chemical formula of ethanol: C2H5OH.


To calculate
the weight of each element, we need to know how many moles of each element ethanol has.
This thing could be easy determined just looking at the subscripts of each constituent
element. Therefore ethanol has : 2 mols of carbon, 1 mole of oxygen and 6 mols of
hydrogen.


We'll calculate the mass of these
elements:


Mass of carbon: 2 mols* 12.01g/mol = 24.02
grams


Mass of oxygen: 1mol*16g/mol = 16
grams


Mass of hydrogen: 6 moles*1.01 g/mol = 6.06
grams


Now, we'll add the results to determine the mass of 1
mol of ethanol:


Mass of C2H5OH = 24.02 + 16 + 6.06 = 46.08
g


Now, we'll determine the percent composition of each
element:


mass percent of C: (24.02/46.08)*100% =
52.14%


mass percent of O: (16/46.08)*100% =
34.77%


mass percent of H: (6.06/46.08)*100% =
13.15%


The requested mass percents are:
52.14% ; 34.77% ; 13.15%.

No comments:

Post a Comment

What is the meaning of the 4th stanza of Eliot's Preludes, especially the lines "I am moved by fancies...Infinitely suffering thing".

A century old this year, T.S. Eliot's Preludes raises the curtain on his great modernist masterpieces, The Love...