sin2x/sinx - cos2x/cosx =
secx
We will start from the L.H.S and prove the
identity.
We know that:
sin2x
= 2sinx*cosx
cos2x = 2cos^2 x -
1
We will substitute in
L.H.S.
=> 2sinxcosx/sinx - (2cos^2
x-1)/cosx
==> 2cosx - 2cos^2 x/cosx +
1/cosx
==> 2cosx - 2cosx +
1/cosx
Reduce 2cosx
Now we
know that secx = 1/cosx
==> 1/cosx = sec
x.........R.H.S
Then the identity "(sin 2x /
sinx) - (cos 2x / cos x) = sec x" is TRUE.
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