sin2x/sinx - cos2x/cosx =
            secx
We will start from the L.H.S and prove the
            identity.
We know that:
 sin2x
            = 2sinx*cosx
cos2x = 2cos^2 x -
            1
We will substitute in
            L.H.S.
=> 2sinxcosx/sinx  - (2cos^2
            x-1)/cosx
==> 2cosx - 2cos^2 x/cosx  +
            1/cosx
==> 2cosx - 2cosx +
            1/cosx
Reduce 2cosx
Now we
            know that secx = 1/cosx
==> 1/cosx = sec
            x.........R.H.S
Then the identity "(sin 2x /
            sinx) - (cos 2x / cos x) = sec x" is TRUE.
No comments:
Post a Comment