We'll have to apply the following identity to prove the
given expression:
sin(a-b) = sin a*cos b - sin b*cos
a
Let a = /2 and b =
x
sin ( /2 - x) = sin
/2*cos x - sin x* cos
/2
But sin /2 = 1 and cos
/2 =
0
sin ( /2 - x) = 1*cos x - sin
x*0
sin ( /2 - x) = cos
x
Therefore, the given expression sin (
/2 - x) = cos x represents an identity.
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