This is an elementary trigonometric equation and we'll use
the following pattern to solve it:
sin x =
a
x = ` ``(-1)^(k)` arcsin a + `pi`
*k
Let a = 1/5
Since 1/5
< 1, therefore there are values of x for the sine function to be
possible.
sin x = 1/5
x =
`(-1)^(k)` arcsin (1/5) + `pi` *k
x = `(-1)^(k)` *11.53 +
`pi` *k
The solutions of the equation belong
to the set {`(-1)^(k)`11.53 + `pi` *k/ k`in`Z }.
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