To calculate the area, we'll have to evaluate the improper
integral of the function f(x) = 1/(x^0.6) = 1/x^(6/10) =
1/x^(3/5)
y
dx/x^(3/5) = lim dx/x^(3/5)
1
y-> 1
We'll evaluate the definte integral using
Leibniz Newton
formula:
y
dx/x^(3/5) =
F(y) - F(1)
1
We'll calculate
the indefinite integral of the function:
x^(-3/5)dx =
x^(-3/5 + 1)/(-3/5 + 1) + c
x^(-3/5)dx = 5x^(2/5)/2 +
c
F(y) - F(1) = 5y^(2/5)/2 -
5/2
Now, we'll evaluate the
limit:
lim [F(y) - F(1)] = lim F(y) - lim
F(1)
y-> y->
y->
lim [F(y) - F(1)] = -
5/2
y->
lim [F(y) -
F(1)] =
y->
Since
the limit is infinite, the integral is divergent and the area is not
finite.
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