Find (fog) if f(x)=x^3+1 and g(x)=x+1?

To determine the result of compositions of the given
function, all we need to do is to plug in the second function listed g(x) into the first
function f(x).

Conclusion: We'll replace x by g(x) in the
expression of f(x).

(fog)(x) = [f(g(x))] = [g(x)]^3 +
1

(fog)(x) = (x+1)^3 + 1

This
sum of cubes returns the product:

a^3 + b^3 = (a+b)(a^2 -
ab + b^2)

(x+1)^3 + 1 = (x + 1 + 1)[(x+1)^2 - x - 1 +
1]

(x+1)^3 + 1 = (x+2)(x^2 + 2x + 1 - x - 1 +
1)

We'll eliminate like terms within the second pair of
brackets:

(x+1)^3 + 1 = (x+2)(x^2 + x +
1)

(x+1)^3 + 1 = x^3 + x^2 + x + 2x^2 + 2x +
2

(x+1)^3 + 1 = x^3 + 3x^2 + 3x +
2

The result of combining the given functions
f and g is: (fog)(x) = x^3 + 3x^2 + 3x + 2.