(3x+2)(2x-5)=ax^2+kx+n What is the value of a-n+k?

All we need to do is to perform the multiplication from
the left side and then to compare the results.

We'll
multiply the brackets:

(3x+2)(2x-5)= 6x^2 - 15x + 4x -
10

We'll combine like
terms:

(3x+2)(2x-5) = 6x^2 - 11x -
10

Comparing both sides, we'll
get:

6x^2 - 11x - 10 = ax^2 + kx +
n

a = 6 , k = -11 , n =
-10

Now, we'll calculate a - n + k = 6 - (-10) +
(-11)

a - n + k = 6 + 10 -
11

a - n + k =
5

The requested value of a - n + k =
5.