First of all, we'll use the Pythagorean identity to
re-write the second factor of the product:
1 + `tan^(2)` x
= 1/`cos^(2)` x
The left side will
become:
(2`cos^(2)`x - 1 )*(1/`cos^(2)`
x)
Now, we'll remove the brackets from the left and we'll
re-write the identity to be demonstrated:
2 - 1/`cos^(2)` x
= 1 - `tan^(2)` x
We'll use again the Pythagorean identity
to re-write the second term of the difference from the right
side:
1 + `tan^(2)` x = 1/`cos^(2)` x => `tan^(2)` x
= 1/`cos^(2)` x - 1
The identity to be verified will
become:
2 - 1/`cos^(2)` x = 1 - (1/`cos^(2)`x - 1
)
We'll remove the brackets from the right
side:
2 - 1/`cos^(2)` x = 1 - 1/`cos^(2)` x +
1
We'll combine like terms and we'll
get:
2 - 1/`cos^(2)` x = 2 - 1/`cos^(2)`
x
Since LHS = RHS, therefore the given
identity (2`cos^(2)` x - 1)(1+`tan^(2)`x ) = 1 - `tan^(2)` x is
verified.
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