Applying the module property, we'll have to solve two
cases:
1) -5x-2=12
-5x = 12 +
2
-5x = 14
x =
-14/5
-5x - 2 > 0 => -5x > 2 =>
x < -2/5
Since -14/5 < -2/5, the value of x
is accepted as solution of equation.
2)
-5x-2=-12
-5x = -12+2
-5x =
-10
x = 2
-5x-2 `<=`
0
x `>=` -2/5
Since 2
> -2/5, the value of x is accepted as solution of
equation.
The requested solutions of the
equation are: {-14/5 ; 2}.
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