How to use distributive law to multiply complex numbers (2+3i)(1-5i)?

We'll recall the definition of the distributive
law:

(a+b)(c+d)=(a+b)*c +
(a+b)*d

We'll use the distributive law to perform the
multiplication of given complex numbers:

(2+3i)(1-5i) =
(2+3i)*1 + (2+3i)*(-5i)

We'll remove the
brackets:

(2+3i)(1-5i) = 2 + 3i - 10i - 15
`i^2`

But `i^2`  =
-1

(2+3i)(1-5i) = 2 + 3i - 10i +
15

We'll combine real parts and imaginary parts and we'll
get:

(2+3i)(1-5i) = 17 -
7i

The result of multiplication of the given
complex numbers, using distributive law, is (2+3i)(1-5i) = 17 -
7i.