You could also apply quadratic formula to determine the
factors of the given quadratic.
Let's recall the formula
first:
`x_(1,2) = [-b+-sqrt(b^2 -4ac
)]/(2a)`
We'll identify the coefficients
a,b,c:
a = 1 ; b = -10 and c =
25
`x_(1,2) = (10+-sqrt(100 -
100))/2`
`x_(1,2) = 10/2`
`x_1
= x_2 = 5`
We notice that the roots of equation are equal,
therefore we can re-write the quadratic:
`(x - x_1)(x -
x_2) = 0`
`(x - 5)(x - 5) =
0`
`(x - 5)^2 =
0`
Therefore, the quadratic equation will
have two equal solutions `x_1 = x_2 = 5.`
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