rationalize the denominator: 17x over the fourth root of 9x to the 7th power y to the sixth poweralgebra

if your question means 17x/ (4sqrt(9x))^7*y^6), then the
procedures will be as follows

times on top and bottom
4sqrt(729x^3)

the fraction
becomes

(17x*4sqrt(729x^3))/(4
sqrt(9x*729*x^3)*y^6)

Then the inside of the 4th root
becomes 6561 x^4, and the fourth root is just 9 x

put that
into the fraction

it becomes
(17x*4sqrt(729x^3))/(9x*y^6)

the x cancels on the top side
and bottom

it
becomes

17*4sqrt(729x^3)/(9*y^6)

If
you mean the y^6 is not on the bottom, then just leave it aside and multiply it
later

 this question uses that the fourth power of
something could cancel out the fourth root, so the fourth power of 9x is 6561x^4 and we
had 9x already in the 4th root, so we need to time 729x^3 to the 4th root so that there
would be no more radicals on the bottom of the equation, making it
rationalized