Can anyone tell me what is the derivative of sin^2(3x + 8)

We have to find the derivative of [sin(3x +
8)]^2.

Use the chain
rule.

[(sin(3x +
8))^2]'

=> 2*sin(3x + 8)*[sin (3x + 8)]'*[3x +
8]'

=> 2*sin(3x + 8)*cos (3x +
8)*3

=> 6*sin(3x + 8)*cos (3x +
8)

The derivative of [sin(3x + 8)]^2 is
6*sin(3x + 8)*cos (3x + 8)