a.) Essentially, you have one rational expression divided
            by another. So let's simplify each one
            individually:
(x^2-x-6)   =  (x-3)(x+2)  = 
            (x-3)
(x^2-4)          (x-2)(x+2)     
            (x+2)
In the second step, in its factored form, we find the
            restrictions for the denominator are x cannot equal positive or negative
            2.
Repeat for the second
            expression:
(x^2-2x+1)  =  (x-2)(x+1)  = 
            (x-2)
(x^2-1)            (x-1)(x+1)     
            (x-1)
Our restrictions here: x cannot be positive or
            negative 1.
Division is the same as multiplying by the
            reciprocal. Now take the first simplified expression and multiply it by the reciprocal
            of the second.
(x-3)
            (x-1)
(x+2) (x-2)     with the given restrictions x is not
            1, -1, 2, -2
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