First, we'll perform the subtraction from numerator. To
subtract the given fractions they must have the same
denominator.
1/(3+x) - 1/3 = [3 -
(3+x)]/3(3+x)
We'll remove the
brackets:
1/(3+x) - 1/3 =
(3-3-x)/3(3+x)
1/(3+x) - 1/3 =
-x/3(3+x)
Now, we'll re-write the
fraction:
[1/(3+x) - 1/3]/x =
-x/3x(3+x)
We'll simplify and we'll
get:
[1/(3+x) - 1/3]/x = -1/(9 +
3x)
The simplified fraction is -1/(9 +
3x).
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