What is the indefinite integral of e^(1/x)/x^2?

We'll use the substitution method to solve the indefinite
integral.

Let 1/x = t.

We'll
differentiate both sides;

-dx/x^2 = dt => dx/x^2 =
-dt

`int`[e^(1/x)]dx/x^2 = - `int`
(e^t)dt

`int` - ` ` (e^t)dt = - e^t +
C

The requested indefinite integral of the
function is `int`[e^(1/x)]dx/x^2 = -e^(1/x) + C.