Thursday, December 12, 2013

How to integrate the function y=e^(square root x)/square root x?

We'll use the substitution technique to evaluate the
indefinite integral of the given function.


Let `sqrt(x)` =
t => dx/2`sqrt(x)` = dt => dx/`sqrt(x)` =
2dt


`int` e^(`sqrt(x)` ) dx/`sqrt(x)` = 2`int` e^t
dt


2`int` e^t dt = 2 e^t +
C


`int` e^`sqrt(x)` dx/`sqrt(x)` = 2e^`sqrt(x)` +
C


The requested indefinite integral of the
given function is `int` e^`sqrt(x)` dx/`sqrt(x)` = 2e^`sqrt(x)` +
C.

No comments:

Post a Comment

What is the meaning of the 4th stanza of Eliot's Preludes, especially the lines "I am moved by fancies...Infinitely suffering thing".

A century old this year, T.S. Eliot's Preludes raises the curtain on his great modernist masterpieces, The Love...