Thursday, December 12, 2013

How to integrate the function y=e^(square root x)/square root x?

We'll use the substitution technique to evaluate the
indefinite integral of the given function.


Let =
t => dx/2 = dt => dx/ =
2dt


e^( ) dx/ = 2 e^t
dt


2 e^t dt = 2 e^t +
C


e^ dx/ = 2e^ +
C


The requested indefinite integral of the
given function is e^ dx/ = 2e^ +
C.

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