The system can be solved either using elimination method,
or substitution method.
We'll choose elimination method to
remove y variable. For this reason we'll multiply the 2nd equation by
3:
3x + 3y - 6 = 0
We'll add
this equation to the 1st equation of the system:
3x + 3y -
6 + 2x - 3y + 1 = 0
We'll eliminate variable
y:
5x - 5 = 0
We'll isolate 5x
to the left side, adding 5 both sides:
5x =
5
x = 1
We'll replace x by 1
within the second equation, to determine y:
1 + y - 2 =
0
y = 2 - 1
y =
1
The solution of the system of independent
equations is (1 ; 1).
No comments:
Post a Comment