The system can be solved either using elimination method,
            or substitution method.
We'll choose elimination method to
            remove y variable. For this reason we'll multiply the 2nd equation by
            3:
3x + 3y - 6 = 0
We'll add
            this equation to the 1st equation of the system:
3x + 3y -
            6 + 2x - 3y + 1 = 0
We'll eliminate variable
            y:
5x - 5 = 0
We'll isolate 5x
            to the left side, adding 5 both sides:
5x =
            5
x = 1
We'll replace x by 1
            within the second equation, to determine y:
1 + y - 2 =
            0
y = 2 - 1
y =
            1
The solution of the system of independent
            equations is (1 ; 1).
 
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