expression:
cos (a+b) = cos a*cos b - sin b*sin
a
Let a = x and b = 2`pi`
cos (`x+ 2pi` ) = cos
x*cos `2pi` - sin `2pi` *sin x
But sin `2pi` = 0 and cos 2 =
1
cos (x+2`pi` ) = cos x*1 - 0*sin x
cos (x +
2`pi` ) = cos x
Therefore, the given identity cos
(x+2`pi` ) = cos x is demonstrated.
No comments:
Post a Comment