Since all the angles of triangle BCD are equal, that means
that the triangle BCD is equilateral, therefore BD = BC = CD =
2.
Since ABCD is parallelogram, then BC=AD = 2 and AB = CD
= 2.
The perimeter of the parallelogram ABCD
is:
P = AB+BC+CD+AD
P =
4*AB
P = 4*2
P = 8
units
The requested perimeter of the
parallelogram ABCD is of 8 units.
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