We'll manage the LHS.
We'll
write the formula that writes the sine of double angle in terms of sine and cosine of
the angle.
sin 2x = 2 sin x*cos
x
Now, we'll multiply and divide by cos x the right side,
to create the tangent function:
sin 2x = 2 sin x*cos x*cos
x/cos x
sin 2x = 2 tan x*
x
But, from Pythagorean identity, we'll
have:
1 + x = 1/
x =>
x
= 1/(1+ x)
sin 2x = 2 tan x/(1 +
x)
Therefore, the identity sin 2x = 2 tan
x/(1 + x) is verified.
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