Solve 1/3(x-3)

First you need to distribute (multiply 1/3 by x and -3).
 This will give you

1/3x-1<(x-2)/4 I'm assuming that
x-2 is all over 4 on the right side.

Then you'll have to
multply both sides by 4 to get the x-2 alone on the right side.  This will give
you:

4/3x-4<x-2 Now you need to get the x's
together.  Do this by subtracting x from each side.  This leaves you
with:

1/3x-4<-2 Now it's much more simple, just add
4 to each side:

1/3x<2 Last, divide by 1/3 or
multply by 3 on each side and
get:

x<6

Hopefully
that helps.