A worker give an impulse of 4,1 N*s to a stationary object of 0,21 kg. What is the speed of the object after impact.

We'll recall the fact that the impulse represents the
change in momentum of an object.

I = F*delta
t

F is the force applied to the object over the time
interval delta t

But F = m*a => I = m*a*delta
t

But a = delta v/delta t => I = m*delta v*delta
t/delta t

I = m*delta v
(1)

delta v = vf - vi

vf is
the final speed of the object and vi is the initial speed of the
object.

We'll plug into the equation (1) the given
information:

4.1 = 0.21*(Vf -
0).

The initial speed is zero since the object is
stationary, at first.

4.1 = 0.21*Vf => vf =
4.1/0.21

vf = 19.52
m/s

Therefore, the speed of the object, after
the impact, is of 19.52 m/s.