Find the solutions of equation 25x^2-36=0?

This equation could be solved in many
ways.

One way is to notice that the given equation is a
difference of two squares that returns the special
products:

`25x^2 - 36 = (5x - 6)(5x +
6)`

We'll re-write the
equation:

`(5x - 6)(5x + 6) =
0`

We'll cancel each factor and we'll
get:

`5x - 6 = 0`

`5x =
6`

`x = 6/5`

`5x + 6 =
0`

`5x = -6`

`x =
-6/5`

Another way to solve this equation is to add 36 both
sides:

`25x^2 = 36`

We'll
divide both sides by 25:

`x^2 =
36/25`

`x_(1,2) =
+-sqrt(36/25)`

`x_(1,2) =
+-6/5`

Any method you chose to solve, you'll
get the solutions of the equation `x_1 = 6/5 and x_2 =
-6/5.`