What is the derivative of the function f(x)=e^3+pi^(-1)?

We'll examine each term of the given function. The
mathematical constant e is an irrational number and pi is also a mathematical constant
that gives the ratio of a circle to it's diameter.

Being an
addition of constant functions, the function f(x) is a constant, therefore the
derivative of a constant function is zero.

We'll
differentiate the function with respect to
x:

f'(x)=[e^3+pi^(-1)]'

f'(x)
= 0 + 0

f'(x) =
0

Therefore, the requested derivative of the
function is f'(x) = 0.