Monday, March 24, 2014

What is the integral of Sin^2 x Cos^3 x dx?

`int sin^2 x cos^3 x dx = int sin^2 x cos^2 x cos x
`



`= int sin^2 x (1- sin^2 x) cos x
`


put 



`therefore
int sin^2 x (1- sin^2 x) cos x dx = int [t^2 (1-t^2)] dt
`



`= int (t^2 - t^4 ) dt
`



`= (t^3)/3 - (t^5)/5 + c
`


now plug in `t` value as `sin
x`


required integral =`1/3 sin^3 x - 1/5 sin^5 x+
c`

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