well using the logarithm differentation is right, here is
            also another way to do it, which is by the exponent rule and the chain
            rule.
The chain rule states that you split a function into
            two functions, differentiate the outside function, leave the inside alone, then
            differentiate the inside function.
2^(2x+3) is basically
            two functions. One is 2^y , another is y=2X+3
we know by
            the exponent rule
differentation of A^X (A is a
            constant)=A^X ln A
so by the chain
            rule
it is ln 2 * 2^ Y * 2
the
            two at the end is the dervative of the inside function
well
            Y= 2x+3
it is 2*ln2*
            2^(2X+3)
btw, the log laws state that 2 ln 2 = ln (2^2)=ln
            4
so the derivative
            is
ln 4
            *(2^(2x+3))
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