We'll have to use the following formula in order to prove
the given expression:
sin (a+b) = sin a*cos b + sin b*cos
a
Let a = x and b = 2`pi`
sin
(x+ 2`pi` ) = sin x*cos 2`pi` + sin 2`pi` *cos x
But sin
2`pi` = 0 and cos 2`pi` = 1
sin (x+2`pi` ) = sin x*1 +
0*cos x
sin (x + 2`pi` ) = sin
x
Therefore, the given identity sin (x+2`pi`
) = sin x is verified.
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