To discover the elements of the set, we'll have to solve
the inequality. We'll recall the property of absolute
value:
|x|<c <=> -c < x
< c
According to this property, we'll
have:
-3 < x - 2 <
3
We'll solve the left
inequality:
-3 < x -
2
We'll isolate x to the
right:
-3 + 2 < x
-1
< x
We'll solve the right
inequality:
x - 2< 3
x
< 3 + 2
x <
5
The integer element located between -1 and 5, except the
values -1 and 5, are: {0 , 1 , 2 , 3 ,
4}.
Therefore, the elements of the set B,
whose property is |x - 2|< 3 are {0 , 1 , 2 , 3 ,
4}.
No comments:
Post a Comment