`c=(ab)/(a+b)` solve for
a
first multiply both sides by (a+b) to get rid of
fraction
`c(a+b)=ab`
Now
distribute
`ac+bc=ab`
Now we
want to get all the terms with a as a factor on one side and everything else on the
other
`ac-ab=-bc`
now factor
out the a
`a(c-b)=-bc`
Now
divide by
`c-b`
`a=-(bc)/(c-b)`
And we
can get rid of the negative sign by noting
`(c-b)=-(b-c)`
To get our final answer `a =
(bc)/(b-c)`
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