Calculate the equation (n+4)^2-(n-2)^2-12n=________?

we are solving for the expression (n + 4)^2 - (n - 2)^2 -
12n

>(n+4)^2 also means (n + 4)(n + 4), the same
goes to (n - 2)^2, we have:

(n + 4)(n + 4) - (n - 2)(n - 2)
- 12n

>Now let's factor (FOIL), we
have:

(n^2 + 4n + 4n + 8) - (n^2 - 2n - 2n + 4) -
12n

(n^2 + 8n + 8) - (n^2 - 4n + 4) -
12n

>You thenuse polinomial operation, we
have:

n^2 + 8n + 8 - n^2 + 4n - 4 -
12n

12n  +  4 - 12n

>
Our final answer is 4 since 12n - 12n = 0, and we are left with
4

Hope I helped......