Sunday, May 3, 2015

You need to enclose a 250 square foot section with a fence that costs $1.50 per yard. what dimensions would you use to minimize the cost.

Width in yards = w
Lenght in yards =
l


The total area is 250 square
feet.


Fence costs $1.50 per yard or $0.50 per
foot.


Total area = w*l = 250 square feet.
(1)


Perimeter = 2w + 2l =
2(w+l)


Cost = Perimeter in feet times cost per
foot.
C = 0.50(2(w + l) = 1(w+l) = w+l (2)


From
(1) l = 250/w and we substitute into (2) to get


C = w +
250/w   We want to minimize this, so take the
derivative.


C' = 1 - 250/w^2   C will be at a minimum or
maximum when C' = 0.


1 - 250/w^2 = 0     Solve for
w.


1 = 250/w^2


w^2 =
250


w = 50 feet  (we reject the negative square root
because width is always > 0.


if w = 50 then l = 50 
since w*l = 250.   Cost = (50+50) = $100

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