Solve the following by elimination method: 2x 3x

(1) 2x-3y=5
(2)
3x-(2y-3)/5=4

Simplify (2)
(5)3x - (5)(2y-3)/5 =
4(5)
15x - 2y + 3 = 20
(3) 15x - 2y =
17

2x - 3y = 5 multiply by -2 to get -4x + 6y = -10  
(4)
15x - 2y = 23 multiply by 3 to get 45x - 6y = 51  
(5)

Now add (4) and (5) to
get

41x = 41  and solving for x we
get

x = 1

To find y we
substitute x = 1 into (1) and solve for
y
2(1)-3y=5

3y = 2 - 5
3y =
-3
y = -1

Check the answers in the 2nd
equation
3x-(2y-3)/5=4
3(1) - (2(-1)-3)/5 = 4
3 - (-5)/5 =
4
3 - (-1) = 4
4 = 4  Checks...

So our
answer is (1, -1)